JEE Main 202125 Jul, Morning shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002The term independent of 'x' in the expansion of (x+1x2/3−x1/3+1−x−1x−x1/2)10{\left( {{{x + 1} \over {{x^{2/3}} - {x^{1/3}} + 1}} - {{x - 1} \over {x - {x^{1/2}}}}} \right)^{10}}(x2/3−x1/3+1x+1−x−x1/2x−1)10, where x ≠\ne= 0, 1 is equal to ______________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution