JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002If ∑r=010(10r+1−110r)⋅11Cr+1=α11−11111010\sum_{r=0}^{10} \left(\frac{10^{r+1} - 1}{10^r}\right) \cdot {}^{11}C_{r+1} = \frac{\alpha^{11} - 11^{11}}{10^{10}}∑r=010(10r10r+1−1)⋅11Cr+1=1010α11−1111, then α\alphaα is equal to:AOption A. 15BOption B. 11COption C. 24DOption D. 20CheckSkip · show solution
