The sum of the coefficients of x⁴⁹⁹ and x⁵⁰⁰ in (1+x)¹⁰⁰⁰ + x(1+x)⁹⁹⁹ + x²(1+x)⁹⁹⁸ + + x¹⁰⁰⁰ is:

Binomial Theorem and Its Simple Applications: JEE Main 2026 Mathematics question

JEE Main 2026 · 28 Jan, Evening shift · Q13

JEE Main 202628 Jan, Evening shiftMathematicsEasyBinomial Theorem and Its Simple Applications131× since 2002

The sum of the coefficients of

x^{499}

and

x^{500}

(1+x)^{1000} + x(1+x)^{999} + x^2(1+x)^{998} + \ldots + x^{1000}

is :

JEE Main 2026 · 28 Jan, Evening shift · Q13

JEE Main 202628 Jan, Evening shiftMathematicsEasyBinomial Theorem and Its Simple Applications131× since 2002

The sum of the coefficients of

x^{499}

and

x^{500}

(1+x)^{1000} + x(1+x)^{999} + x^2(1+x)^{998} + \ldots + x^{1000}

is :