The number of optically active products obtained from the complete ozonolysis of the given compound is: H₃C - CH = CH - CH(CH₃)-CH = CH - CH(CH₃)-CH = CH - CH₃ (the two CH(CH₃) carbons are drawn with wedge/dash stereochemistry)

Hydrocarbons: JEE Main 2025 Chemistry question

JEE Main 2025 · 7 Apr, Evening shift · Q63

JEE Main 20257 Apr, Evening shiftChemistryMediumHydrocarbons29× since 2002

The number of optically active products obtained from the complete ozonolysis of the given compound is :

\mathrm{H_3C{-}CH{=}CH{-}CH(CH_3){-}CH{=}CH{-}CH(CH_3){-}CH{=}CH{-}CH_3}

(the two

\mathrm{CH(CH_3)}

carbons are drawn with wedge/dash stereochemistry)

JEE Main 2025 · 7 Apr, Evening shift · Q63

JEE Main 20257 Apr, Evening shiftChemistryMediumHydrocarbons29× since 2002

The number of optically active products obtained from the complete ozonolysis of the given compound is :

\mathrm{H_3C{-}CH{=}CH{-}CH(CH_3){-}CH{=}CH{-}CH(CH_3){-}CH{=}CH{-}CH_3}

(the two

\mathrm{CH(CH_3)}

carbons are drawn with wedge/dash stereochemistry)