An alkane (Y) requires 8 moles of oxygen for complete combustion and on chlorination with Cl₂/hν, (Y) gives only one monochlorinated product (Z). The total number of primary carbon atoms in (Y) is _ _ _.

Hydrocarbons: JEE Main 2026 Chemistry question

JEE Main 2026 · 6 Apr, Evening shift · Q72

JEE Main 20266 Apr, Evening shiftChemistryMediumHydrocarbons29× since 2002

An alkane (Y) requires 8 moles of oxygen for complete combustion and on chlorination with

\mathrm{Cl_2}/h\nu

, (Y) gives only one monochlorinated product (Z). The total number of primary carbon atoms in (Y) is ______.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2026 Hydrocarbons Question with Solution (6 Apr Evening shift, Q72) | JEE Arc

JEE Main 2026 · 6 Apr, Evening shift · Q72

JEE Main 20266 Apr, Evening shiftChemistryMediumHydrocarbons29× since 2002

An alkane (Y) requires 8 moles of oxygen for complete combustion and on chlorination with

\mathrm{Cl_2}/h\nu

, (Y) gives only one monochlorinated product (Z). The total number of primary carbon atoms in (Y) is ______.

Your answerType your answer. Integers and decimals are accepted.