The minimum frequency of photon required to break a particle of mass 15.348 amu into 4 α particles is _ _ _ kHz. [mass of He nucleus = 4.002 amu, 1 amu =1.66×10⁻²⁷ kg, h=6.6×10⁻³⁴ J.s and c=3×10⁸ m/s]

Atoms and Nuclei: JEE Main 2026 Physics question

JEE Main 2026 · 22 Jan, Morning shift · Q42

JEE Main 202622 Jan, Morning shiftPhysicsMediumAtoms and Nuclei183× since 2002

The minimum frequency of photon required to break a particle of mass 15.348 amu into 4

\alpha

particles is ______ kHz. [mass of He nucleus = 4.002 amu, 1 amu

=1.66\times10^{-27}

kg,

h=6.6\times10^{-34}

J.s and

c=3\times10^{8}

m/s]