The binding energy per nucleon of ²⁰⁹₈₃Bi is _ _ _ MeV. [Take m(²⁰⁹₈₃Bi)=208.980388 u, m p =1.007825 u, m n =1.008665 u, 1 u = 931 MeV/c ² ]

Atoms and Nuclei: JEE Main 2026 Physics question

JEE Main 2026 · 2 Apr, Evening shift · Q44

JEE Main 20262 Apr, Evening shiftPhysicsEasyAtoms and Nuclei183× since 2002

The binding energy per nucleon of

{}^{209}_{83}Bi

is ______ MeV. [Take

m({}^{209}_{83}Bi)=208.980388

m_p=1.007825

m_n=1.008665

u, 1 u = 931 MeV/c

^2

]

JEE Main 2026 · 2 Apr, Evening shift · Q44

JEE Main 20262 Apr, Evening shiftPhysicsEasyAtoms and Nuclei183× since 2002

The binding energy per nucleon of

{}^{209}_{83}Bi

is ______ MeV. [Take

m({}^{209}_{83}Bi)=208.980388

m_p=1.007825

m_n=1.008665

u, 1 u = 931 MeV/c

^2

]