JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumSequence and Series179× since 2002For positive integers nnn, if 4an=(n2+5n+6)4a_n = (n^2 + 5n + 6)4an=(n2+5n+6) and Sn=∑k=1n(1ak)S_n = \sum_{k=1}^{n} \left(\frac{1}{a_k}\right)Sn=∑k=1n(ak1), then the value of 507S2025507 S_{2025}507S2025 is:AOption A. 540BOption B. 675COption C. 1350DOption D. 135CheckSkip · show solution