JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumSequence and Series179× since 2002Let a1,a2,a3,…a_1,a_2,a_3,\dotsa1,a2,a3,… be in an A.P. such that ∑k=112a2k−1=−725a1\displaystyle\sum_{k=1}^{12}a_{2k-1}=-\tfrac{72}{5}a_1k=1∑12a2k−1=−572a1, a1≠0a_1\neq0a1=0. If ∑k=1nak=0\displaystyle\sum_{k=1}^n a_k=0k=1∑nak=0, then nnn is:AOption A. 11BOption B. 10COption C. 18DOption D. 17CheckSkip · show solution
