JEE Main 20204 Sep, Morning shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002Let (2x2+3x+4)10=∑r=020arxr{\left( {2{x^2} + 3x + 4} \right)^{10}} = \sum\limits_{r = 0}^{20} {{a_r}{x^r}}(2x2+3x+4)10=r=0∑20arxr Then a7a13{{{a_7}} \over {{a_{13}}}}a13a7 is equal to ______.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution