JEE Main 202225 Jul, Morning shiftMathematicsMediumSequence and Series179× since 2002Let a1=b1=1,an=an−1+2a_{1}=b_{1}=1, a_{n}=a_{n-1}+2a1=b1=1,an=an−1+2 and bn=an+bn−1b_{n}=a_{n}+b_{n-1}bn=an+bn−1 for every natural number n⩾2n \geqslant 2n⩾2. Then ∑n=115an.bn\sum\limits_{n = 1}^{15} {{a_n}.{b_n}}n=1∑15an.bn is equal to ___________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
