If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is _ _ _ _ × 10⁻² ~MeV. (Given 1 u=931 ~MeV / c², atomic mass of helium =4.002603 u)

Atoms and Nuclei: JEE Main 2024 Physics question

JEE Main 2024 · 5 Apr, Morning shift · Q56

JEE Main 20245 Apr, Morning shiftPhysicsMediumAtoms and Nuclei183× since 2002

If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is ________

\times 10^{-2} \mathrm{~MeV}

. (Given

1 \mathrm{u}=931 \mathrm{~MeV} / \mathrm{c}^2

, atomic mass of helium

=4.002603 \mathrm{u}

)

Your answerType your answer. Integers and decimals are accepted.

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