JEE Main 20265 Apr, Evening shiftMathematicsEasySequence and Series179× since 2002If the sum of the first 10 terms of the series 11+14×4+21+24×4+31+34×4+41+44×4+…\frac{1}{1+1^4\times4}+\frac{2}{1+2^4\times4}+\frac{3}{1+3^4\times4}+\frac{4}{1+4^4\times4}+\dots1+14×41+1+24×42+1+34×43+1+44×44+… is mn\frac{m}{n}nm, gcd(m,n)=1\gcd(m,n)=1gcd(m,n)=1, then m+nm+nm+n is equal to :AOption A. 256BOption B. 264COption C. 276DOption D. 284CheckSkip · show solution
