JEE Main 20245 Apr, Morning shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002If the constant term in the expansion of (1+2x−3x3)(32x2−13x)9\left(1+2 x-3 x^3\right)\left(\frac{3}{2} x^2-\frac{1}{3 x}\right)^9(1+2x−3x3)(23x2−3x1)9 is p\mathrm{p}p, then 108p108 \mathrm{p}108p is equal to ________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
