If the binding energy of ground state electron in a hydrogen atom is 13.6 eV, then, the energy required to remove the electron from the second excited state of Li²⁺ will be: x × 10⁻¹ eV. The value of x is _ _ _ _.

Atoms and Nuclei: JEE Main 2023 Physics question

JEE Main 2023 · 31 Jan, Evening shift · Q57

JEE Main 202331 Jan, Evening shiftPhysicsMediumAtoms and Nuclei183× since 2002

If the binding energy of ground state electron in a hydrogen atom is

13.6\, \mathrm{eV}

, then, the energy required to remove the electron from the second excited state of

\mathrm{Li}^{2+}

will be :

x \times 10^{-1} \mathrm{eV}

. The value of

x

is ________.

Your answerType your answer. Integers and decimals are accepted.

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