JEE Main 202621 Jan, Evening shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002If (115C0+115C1)(115C1+115C2)⋯(115C12+115C13)=α1314C0 14C1⋯14C12\left(\frac{1}{^{15}C_0}+\frac{1}{^{15}C_1}\right)\left(\frac{1}{^{15}C_1}+\frac{1}{^{15}C_2}\right)\cdots\left(\frac{1}{^{15}C_{12}}+\frac{1}{^{15}C_{13}}\right)=\frac{\alpha^{13}}{^{14}C_0\,^{14}C_1\cdots{}^{14}C_{12}}(15C01+15C11)(15C11+15C21)⋯(15C121+15C131)=14C014C1⋯14C12α13, then 30α30\alpha30α is equal to ______.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution