JEE Main 20268 Apr, Evening shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002If 26(233(12C2)+255(12C4)+277(12C6)+⋯+21313(12C12))=313−α26\left(\frac{2^3}{3}\left({}^{12}C_2\right)+\frac{2^5}{5}\left({}^{12}C_4\right)+\frac{2^7}{7}\left({}^{12}C_6\right)+\cdots+\frac{2^{13}}{13}\left({}^{12}C_{12}\right)\right)=3^{13}-\alpha26(323(12C2)+525(12C4)+727(12C6)+⋯+13213(12C12))=313−α, then α\alphaα is equal to :AOption A. 45BOption B. 48COption C. 51DOption D. 54CheckSkip · show solution
