JEE Main 20266 Apr, Evening shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002If (1−x3)10=∑r=010arxr(1−x)30−2r(1-x^3)^{10}=\displaystyle\sum_{r=0}^{10}a_rx^r(1-x)^{30-2r}(1−x3)10=r=0∑10arxr(1−x)30−2r, then 9a9a10\dfrac{9a_9}{a_{10}}a109a9 is equal to ______.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution