JEE Main 202120 Jul, Evening shiftMathematicsMediumSequence and Series179× since 2002For k ∈\in∈ N, let 1α(α+1)(α+2).........(α+20)=∑K=020Akα+k{1 \over {\alpha (\alpha + 1)(\alpha + 2).........(\alpha + 20)}} = \sum\limits_{K = 0}^{20} {{{{A_k}} \over {\alpha + k}}}α(α+1)(α+2).........(α+20)1=K=0∑20α+kAk, where α>0\alpha > 0α>0. Then the value of 100(A14+A15A13)2100{\left( {{{{A_{14}} + {A_{15}}} \over {{A_{13}}}}} \right)^2}100(A13A14+A15)2 is equal to _____________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
