JEE Main 202624 Jan, Morning shiftMathematicsEasySequence and Series179× since 2002Consider an A.P.: a1,a2,…,ana_1, a_2, \ldots, a_na1,a2,…,an; a1>0a_1 > 0a1>0. If a2−a1=−34a_2 - a_1 = \frac{-3}{4}a2−a1=4−3, an=14a1a_n = \frac{1}{4}a_1an=41a1, and ∑i=1nai=5252\sum_{i=1}^{n} a_i = \frac{525}{2}∑i=1nai=2525, then ∑i=117ai\sum_{i=1}^{17} a_i∑i=117ai is equal toAOption A. 476476476BOption B. 136136136COption C. 238238238DOption D. 952952952CheckSkip · show solution
