A common example of alpha decay is ₉₂²³⁸ U ₉₀²³⁴ Th+ ₂ He⁴+Q Given: ₉₂²³⁸ U=238.05060 ~u, ₉₀²³⁴ Th=234.04360 ~u, ₂⁴ He=4.00260 ~u and 1 u=931.5 MeV/(c²) The energy released (Q) during the alpha decay of ₉₂²³⁸ U is _ _ _ _ _ MeV

Atoms and Nuclei: JEE Main 2023 Physics question

JEE Main 2023 · 12 Apr, Morning shift · Q52

JEE Main 202312 Apr, Morning shiftPhysicsHardAtoms and Nuclei183× since 2002

A common example of alpha decay is

{ }_{92}^{238} \mathrm{U} \longrightarrow{ }_{90}^{234} \mathrm{Th}+{ }_{2} \mathrm{He}^{4}+\mathrm{Q}

Given :

{ }_{92}^{238} \mathrm{U}=238.05060 ~\mathrm{u}

{ }_{90}^{234} \mathrm{Th}=234.04360 ~\mathrm{u}

{ }_{2}^{4} \mathrm{He}=4.00260 ~\mathrm{u}

and

1 \mathrm{u}=931.5 \frac{\mathrm{MeV}}{c^{2}}

The energy released

(Q)

during the alpha decay of

{ }_{92}^{238} \mathrm{U}

is __________ MeV

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2023 Atoms and Nuclei Question with Answer (12 Apr Morning shift, Q52) | JEE Arc