Organic Compounds Containing Oxygen

Consider the following reaction. $\mathrm{C_6H_5{-}O{-}CH_2{-}C_6H_5}+\mathrm{HI}\to$ Product. Statement I : In the above reaction, product formed will be a mixture of benzyl alcohol and iodobenzene. Statement II : In the above reaction, the $-\mathrm{O{-}CH_2}-$ bond is cleaved to give the product. In the light of the above statements, choose the correct answer from the options given below :

An organic compound “x” where molar ratio of C, O and H are equal, on treatment with 50% KOH under reflux followed by acidification produced “y”. The most likely structure of “y” is : [Molar mass of 'x' is 58 g mol$^{-1}$]

A molecule (X) with following structure under mild acidic condition is hydrolysed to produce (Y) and (Z). Identify the correct statements about (Y) and (Z). [X: $\mathrm{CH_3-CH=CH-O-C(CH_3)=CH_2}$] A. Both (Y) and (Z) have same molar mass. B. (Y) and (Z) can be distinguished from each other by $\mathrm{NaHCO_3}$. C. (Y) and (Z) react with HCN with same rates. D. (Y) and (Z) undergo addition reaction with 2,4-DNP. Choose the correct answer from the options given below :

Consider the following sequence of reactions to give the major product (X): benzene $\xrightarrow{\text{(i) }\mathrm{CH_3Cl/anhydrous\ AlCl_3}\text{ (ii) }\mathrm{Cl_2/FeCl_3}\text{ (iii) }\mathrm{K_2Cr_2O_7/H_2SO_4}}$ (X) Major Product. P g of the major product (X) formed is reacted with $\mathrm{NaHCO_3}$ solution to liberate a gas which occupied 11.2 dm$^3$ at STP. $P=$ ______ g. (Given molar mass in g mol$^{-1}$ H:1, C:12, O:16, Cl:35.5)

Consider compounds A, B and C with following structural formulae $\mathrm{A = CH_3-CH_2-CH_2-CH_2-CH_2-OH}$, $\mathrm{B = CH_2=CH-CH_2-CH_2-CH_3}$, $\mathrm{C = HO-CH_2-CH_2-CH(OH)-CH_3}$. For the conversion of B from A, reagent (D) required is _________ and structural formula of product (E) obtained when C undergoes same reaction using excess reagent (D) is ________.

One mole of phenol is treated with dilute $\mathrm{HNO_3}$ at 298 K to give a mixture of products. The mixture is separated by steam distillation. The steam volatile compound (X) is separated. The increase in percentage of oxygen in (X) with respect to phenol is _______$\times10^{-1}$% (Given molar mass in g $\mathrm{mol^{-1}}$ H:1, C:12, N:14, O:16)

Given below are two statements : Statement I : Phenols are weakly acidic. Statement II : Therefore they are freely soluble in NaOH solution and are weaker acids than alcohols and water. Choose the most appropriate option :

Complete the following reaction sequence and give the name of major product 'P'. $\mathrm{CH_3CH_2C{\equiv}N}$ $\xrightarrow{\text{(i) }\mathrm{OH^-/H_2O/\Delta}\ \text{(ii) }\mathrm{H_3O^+}\ \text{(iii) }\mathrm{Cl_2/Red\ P}\ \text{(iv) }\mathrm{H_2O}}$ P (Major product)

Given below are two statements : Statement I : The condensation reaction between $\mathrm{CH_3-CH=O}$ and $\mathrm{H_2N-NH-C(=O)-NH_2}$ under optimum pH will produce $\mathrm{CH_3-CH=N-C(=O)-NH-NH_2}$. Statement II : The molecule, $\mathrm{Ph-CH(OH)(O-CH_3)}$ will generate $\mathrm{Ph-CH=O}$ in the presence of dilute acid. In the light of the above statements, choose the correct answer from the options given below :