When light of wavelength 248 nm falls on a metal of threshold energy 3.0 eV, the de-Broglie wavelength of emitted electrons is _ _ _ _ A^(o). (Round off to the Nearest Integer). [ Use: 3 = 1.73, h = 6.63 × 10⁻³4 Js m e = 9.1 × 10⁻³1 kg; c = 3.0 × 10⁸ ms⁻¹; 1eV = 1.6 × 10⁻¹9 J]

Atomic Structure: JEE Main 2021 Chemistry question

JEE Main 2021 · 16 Mar, Morning shift · Q22

JEE Main 202116 Mar, Morning shiftChemistryHardAtomic Structure113× since 2002

When light of wavelength 248 nm falls on a metal of threshold energy 3.0 eV, the de-Broglie wavelength of emitted electrons is _______

\mathop A\limits^o

. (Round off to the Nearest Integer). [ Use :

\sqrt 3

= 1.73, h = 6.63

\times

10^

-

34 Js m_e = 9.1

\times

10^

-

31 kg; c = 3.0

\times

10⁸ ms^

-

1; 1eV = 1.6

\times

10^

-

19 J]

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Atomic Structure Question with Answer (16 Mar Morning shift, Q22) | JEE Arc