Two identical spheres each of mass 2 ~kg and radius 50 ~cm are fixed at the ends of a light rod so that the separation between the centers is 150 ~cm. Then, moment of inertia of the system about an axis perpendicular to the rod and passing through its middle point is x/20 ~kg m², where the value of x is _ _ _ _ _ _.

Rotational Motion: JEE Main 2024 Physics question

JEE Main 2024 · 31 Jan, Evening shift · Q70

JEE Main 202431 Jan, Evening shiftPhysicsHardRotational Motion140× since 2002

Two identical spheres each of mass

2 \mathrm{~kg}

and radius

50 \mathrm{~cm}

are fixed at the ends of a light rod so that the separation between the centers is

150 \mathrm{~cm}

. Then, moment of inertia of the system about an axis perpendicular to the rod and passing through its middle point is

\frac{x}{20} \mathrm{~kg} \mathrm{m^{2 }}

, where the value of

x

is ___________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2024 Rotational Motion Question with Answer (31 Jan Evening shift, Q70) | JEE Arc