Two charges 7 and -4 are placed at (-7 cm, 0, 0) and (7 cm, 0, 0) respectively. Given, ε₀ = 8.85 × 10⁻¹² C² N⁻¹ m⁻², the electrostatic potential energy of the charge configuration is:

Electrostatics: JEE Main 2025 Physics question

JEE Main 2025 · 23 Jan, Evening shift · Q43

JEE Main 202523 Jan, Evening shiftPhysicsMediumElectrostatics167× since 2002

Two charges

7\ \mu\mathrm{c}

and

-4\ \mu\mathrm{c}

are placed at

(-7

cm, 0, 0) and (7 cm, 0, 0) respectively. Given,

\epsilon_0 = 8.85 \times 10^{-12}\ \mathrm{C^2\,N^{-1}\,m^{-2}}

, the electrostatic potential energy of the charge configuration is: