Two charges 7 μC and −2 μC are placed at (−9, 0, 0) cm and (9, 0, 0) cm respectively in an external field E=A/(r²) r, where A=9×10⁵ N/C.m ². Considering the potential at infinity is 0, the electrostatic energy of the configuration is _ _ _ J.

Electrostatics: JEE Main 2026 Physics question

JEE Main 2026 · 23 Jan, Evening shift · Q45

JEE Main 202623 Jan, Evening shiftPhysicsMediumElectrostatics167× since 2002

Two charges 7 μC and −2 μC are placed at (−9, 0, 0) cm and (9, 0, 0) cm respectively in an external field

E=\frac{A}{r^2}\hat r

, where

A=9\times10^5

N/C.m

^2

. Considering the potential at infinity is 0, the electrostatic energy of the configuration is _______J.

JEE Main 2026 Electrostatics Question with Solution (23 Jan Evening shift, Q45) | JEE Arc