MathematicsEasy63×since 2002Q3690The value of loge2ddx(logcosxcosecx)\log _{e} 2 \frac{d}{d x}\left(\log _{\cos x} \operatorname{cosec} x\right)loge2dxd(logcosxcosecx) at x=π4x=\frac{\pi}{4}x=4π isA−22-2 \sqrt{2}−22B222 \sqrt{2}22C−4-4−4D4Check answerSkip