MathematicsEasy63×since 2002Q3688For x > 1, if (2x)^2y = 4e^2x−-−2y, then (1 + log_e 2x)² dydx{{dy} \over {dx}}dxdy is equal to :Ax loge2x−loge2x{{x\,{{\log }_e}2x - {{\log }_e}2} \over x}xxloge2x−loge2Blog_e 2xCx log_e 2xDx loge2x+loge2x{{x\,{{\log }_e}2x + {{\log }_e}2} \over x}xxloge2x+loge2Check answerSkip