JEE Main 20249 Apr, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002The square of the distance of the image of the point (6,1,5)(6,1,5)(6,1,5) in the line x−13=y2=z−24\frac{x-1}{3}=\frac{y}{2}=\frac{z-2}{4}3x−1=2y=4z−2, from the origin is __________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
