JEE Main 202324 Jan, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002The shortest distance between the lines x−23=y+12=z−62{{x - 2} \over 3} = {{y + 1} \over 2} = {{z - 6} \over 2}3x−2=2y+1=2z−6 and x−63=1−y2=z+80{{x - 6} \over 3} = {{1 - y} \over 2} = {{z + 8} \over 0}3x−6=21−y=0z+8 is equal to ________Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution