The resistance of a conductivity cell containing 0.01 M KCl solution at 298 K is 1750 Ω. If the conductivity of 0.01 M KCl solution at 298 K is 0.152 × 10⁻³ S cm⁻¹, then the cell constant of the conductivity cell is _ _ _ _ _ _ × 10⁻³ cm⁻¹.

Redox Reactions and Electrochemistry: JEE Main 2022 Chemistry question

JEE Main 2022 · 24 Jun, Evening shift · Q10

JEE Main 202224 Jun, Evening shiftChemistryMediumRedox Reactions and Electrochemistry138× since 2002

The resistance of a conductivity cell containing 0.01 M KCl solution at 298 K is 1750

\Omega

. If the conductivity of 0.01 M KCl solution at 298 K is 0.152

\times

10^

-

3 S cm^

-

1, then the cell constant of the conductivity cell is ____________

\times

10^

-

3 cm^

-

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2022 Redox Reactions and Electrochemistry Question with Answer (24 Jun Evening shift, Q10) | JEE Arc