MathematicsMedium127×since 2002Q3120The radius of a circle, having minimum area, which touches the curve y = 4 – x² and the lines, y = |x| is :A2(2−1)2\left( {\sqrt 2 - 1} \right)2(2−1)B4(2−1)4\left( {\sqrt 2 - 1} \right)4(2−1)C4(2+1)4\left( {\sqrt 2 + 1} \right)4(2+1)D2(2+1)2\left( {\sqrt 2 + 1} \right)2(2+1)Check answerSkip