MathematicsEasy127×since 2002Q3038If the lines 2x + 3y + 1 + 0 and 3x - y - 4 = 0 lie along diameter of a circle of circumference 10 π10\,\pi10π, then the equation of the circle is :Ax2 + y2+ 2x − 2y− 23 =0{x^2}\, + \,{y^2} + \,2x\, - \,2y - \,23\,\, = 0x2+y2+2x−2y−23=0Bx2 + y2− 2x − 2y− 23 =0{x^2}\, + \,{y^2} - \,2x\, - \,2y - \,23\,\, = 0x2+y2−2x−2y−23=0Cx2 + y2+ 2x + 2y− 23 =0{x^2}\, + \,{y^2} + \,2x\, + \,2y - \,23\,\, = 0x2+y2+2x+2y−23=0Dx2 + y2− 2x + 2y− 23 =0{x^2}\, + \,{y^2} - \,2x\, + \,2y - \,23\,\, = 0x2+y2−2x+2y−23=0Check answerSkip