JEE Main 202523 Jan, Morning shiftPhysicsEasyUnits and Measurements122× since 2002The position of a particle moving on x-axis is given by x(t)=Asint+Bcos2t+Ct2+Dx(t)=A\sin t+B\cos^2 t+Ct^2+Dx(t)=Asint+Bcos2t+Ct2+D, where t is time. The dimension of ABCD\dfrac{ABC}{D}DABC isAOption A. L3T−2\mathrm{L^3T^{-2}}L3T−2BOption B. L\mathrm{L}LCOption C. L2\mathrm{L^2}L2DOption D. L2T−2\mathrm{L^2T^{-2}}L2T−2CheckSkip · show solution