The peak electric field produced by the radiation coming from the 8W bulb at a distance of 10 m is x/10√((μ ₀c)/(π)) V/m. The efficiency of the bulb is 10% and it is a point source. The value of x is _ _ _ _ _ _.

Electromagnetic Waves: JEE Main 2021 Physics question

JEE Main 2021 · 25 Feb, Evening shift · Q61

JEE Main 202125 Feb, Evening shiftPhysicsMediumElectromagnetic Waves120× since 2002

The peak electric field produced by the radiation coming from the 8W bulb at a distance of 10 m is

{x \over {10}}\sqrt {{{{\mu _0}c} \over \pi }} {V \over m}

. The efficiency of the bulb is 10% and it is a point source. The value of x is ___________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Electromagnetic Waves Question with Answer (25 Feb Evening shift, Q61) | JEE Arc

JEE Main 2021 · 25 Feb, Evening shift · Q61

JEE Main 202125 Feb, Evening shiftPhysicsMediumElectromagnetic Waves120× since 2002

The peak electric field produced by the radiation coming from the 8W bulb at a distance of 10 m is

{x \over {10}}\sqrt {{{{\mu _0}c} \over \pi }} {V \over m}

. The efficiency of the bulb is 10% and it is a point source. The value of x is ___________.

Your answerType your answer. Integers and decimals are accepted.