JEE Main 202622 Jan, Morning shiftMathematicsEasyTrigonometry118× since 2002The number of solutions of tan−14x+tan−16x=π6\tan^{-1}4x+\tan^{-1}6x=\frac{\pi}{6}tan−14x+tan−16x=6π, where −126<x<126-\frac{1}{2\sqrt6}<x<\frac{1}{2\sqrt6}−261<x<261, is equal toAOption A. 333BOption B. 111COption C. 000DOption D. 222CheckSkip · show solution