JEE Main 202228 Jun, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002The number of real solutions of the equation e4x+4e3x−58e2x+4ex+1=0{e^{4x}} + 4{e^{3x}} - 58{e^{2x}} + 4{e^x} + 1 = 0e4x+4e3x−58e2x+4ex+1=0 is ___________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution