JEE Main 20241 Feb, Morning shiftMathematicsMediumPermutations and Combinations98× since 2002The number of elements in the set S={(x,y,z):x,y,z∈Z,x+2y+3z=42,x,y,z⩾0}\mathrm{S}=\{(x, y, z): x, y, z \in \mathbf{Z}, x+2 y+3 z=42, x, y, z \geqslant 0\}S={(x,y,z):x,y,z∈Z,x+2y+3z=42,x,y,z⩾0} equals __________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
