The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is 1/x MR², where R is the radius and M is the mass of the semicircular ring. The value of x will be _ _ _ _ _.

Rotational Motion: JEE Main 2023 Physics question

JEE Main 2023 · 8 Apr, Morning shift · Q71

JEE Main 20238 Apr, Morning shiftPhysicsMediumRotational Motion140× since 2002

The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is

\frac{1}{x} \mathrm{MR}^{2}

, where

\mathrm{R}

is the radius and

M

is the mass of the semicircular ring. The value of

x

will be __________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2023 Rotational Motion Question with Answer (8 Apr Morning shift, Q71) | JEE Arc