JEE Main 202522 Jan, Evening shiftChemistryEasyEquilibrium123× since 2002The molar solubility(s) of zirconium phosphate with molecular formula (Zr4+)3(PO43−)4\mathrm{(Zr^{4+})_3(PO_4^{3-})_4}(Zr4+)3(PO43−)4 is given by relation :AOption A. (Ksp9612)1/3\left(\dfrac{K_{sp}}{9612}\right)^{1/3}(9612Ksp)1/3BOption B. (Ksp8435)1/7\left(\dfrac{K_{sp}}{8435}\right)^{1/7}(8435Ksp)1/7COption C. (Ksp5348)1/6\left(\dfrac{K_{sp}}{5348}\right)^{1/6}(5348Ksp)1/6DOption D. (Ksp6912)1/7\left(\dfrac{K_{sp}}{6912}\right)^{1/7}(6912Ksp)1/7CheckSkip · show solution
