MathematicsMedium64×since 2004Q4004The integral ∫dx(1+x)x−x2\int {{{dx} \over {\left( {1 + \sqrt x } \right)\sqrt {x - {x^2}} }}}∫(1+x)x−x2dx is equal to : (where C is a constant of integration.)A−21+x1−x+C- 2\sqrt {{{1 + \sqrt x } \over {1 - \sqrt x }}} + C−21−x1+x+CB−21−x1+x+C- 2\sqrt {{{1 - \sqrt x } \over {1 + \sqrt x }}} + C−21+x1−x+CC−1−x1+x+C- \sqrt {{{1 - \sqrt x } \over {1 + \sqrt x }}} + C−1+x1−x+CD21+x1−x+C2\sqrt {{{1 + \sqrt x } \over {1 - \sqrt x }}} + C21−x1+x+CCheck answerSkip