MathematicsHard64×since 2004Q3995For I(x)=∫sec2x−2022sin2022xdxI(x)=\int \frac{\sec ^{2} x-2022}{\sin ^{2022} x} d xI(x)=∫sin2022xsec2x−2022dx, if I(π4)=21011I\left(\frac{\pi}{4}\right)=2^{1011}I(4π)=21011, thenA31010I(π3)−I(π6)=03^{1010} I\left(\frac{\pi}{3}\right)-I\left(\frac{\pi}{6}\right)=031010I(3π)−I(6π)=0B31010I(π6)−I(π3)=03^{1010} I\left(\frac{\pi}{6}\right)-I\left(\frac{\pi}{3}\right)=031010I(6π)−I(3π)=0C31011I(π3)−I(π6)=03^{1011} I\left(\frac{\pi}{3}\right)-I\left(\frac{\pi}{6}\right)=031011I(3π)−I(6π)=0D31011I(π6)−I(π3)=03^{1011} I\left(\frac{\pi}{6}\right)-I\left(\frac{\pi}{3}\right)=031011I(6π)−I(3π)=0Check answerSkip