JEE Main 20264 Apr, Evening shiftMathematicsEasyIntegral Calculus369× since 2002The integral ∫01cot−1(1+x+x2)dx\int_0^1\cot^{-1}\left(1+x+x^2\right)dx∫01cot−1(1+x+x2)dx is equal to:AOption A. 2tan−12+12loge(54)+π22\tan^{-1}2+\frac12\log_e\left(\frac54\right)+\frac\pi22tan−12+21loge(45)+2πBOption B. 2tan−12+12loge(54)−π22\tan^{-1}2+\frac12\log_e\left(\frac54\right)-\frac\pi22tan−12+21loge(45)−2πCOption C. 2tan−12−12loge(54)+π22\tan^{-1}2-\frac12\log_e\left(\frac54\right)+\frac\pi22tan−12−21loge(45)+2πDOption D. 2tan−12−12loge(54)−π22\tan^{-1}2-\frac12\log_e\left(\frac54\right)-\frac\pi22tan−12−21loge(45)−2πCheckSkip · show solution
