The first order rate constant for the decomposition of CaCO₃ at 700 K is 6.36 × 10⁻³s⁻¹ and activation energy is 209 kJ mol⁻¹. Its rate constant (in s⁻¹) at 600 K is x × 10⁻⁶. The value of x is _ _ _ _ _ _. (Nearest integer) [Given R = 8.31 J K^(- m)ol⁻¹; log 6.36 × 10⁻³ = - 2.19, 10⁻⁴.79 = 1.62 × 10⁻⁵]

Chemical Kinetics: JEE Main 2021 Chemistry question

JEE Main 2021 · 27 Aug, Evening shift · Q6

JEE Main 202127 Aug, Evening shiftChemistryHardChemical Kinetics62× since 2002

The first order rate constant for the decomposition of CaCO₃ at 700 K is 6.36

\times

10^

-

3s^

-

1 and activation energy is 209 kJ mol^

-

1. Its rate constant (in s^

-

1) at 600 K is x

\times

10^

-

6. The value of x is ___________. (Nearest integer) [Given R = 8.31 J K^

-

mol^

-

1; log 6.36

\times

10^

-

3 =

-

2.19, 10^

-

4.79 = 1.62

\times

10^

-

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Chemical Kinetics Question with Answer (27 Aug Evening shift, Q6) | JEE Arc