JEE Main 202311 Apr, Morning shiftPhysicsMediumOscillations and Waves185× since 2002The equation of wave is given by Y=10−2sin2π(160t−0.5x+π/4)\mathrm{Y}=10^{-2} \sin 2 \pi(160 t-0.5 x+\pi / 4)Y=10−2sin2π(160t−0.5x+π/4) where xxx and YYY are in m\mathrm{m}m and t\mathrm{t}t in sss. The speed of the wave is ________ km h−1\mathrm{km} ~\mathrm{h}^{-1}km h−1.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution