The equation of the electric field of an electromagnetic wave propagating through free space is given by: E=√(377) sin (6.27×10³t-2.09×10⁻⁵x) N/C. The average power of the electromagnetic wave is (1/(α)) W/m ². The value of α is _ _ _ (Take √((μ₀)/(ε₀))=377 in SI units)

Electromagnetic Waves: JEE Main 2026 Physics question

JEE Main 2026 · 23 Jan, Morning shift · Q48

JEE Main 202623 Jan, Morning shiftPhysicsMediumElectromagnetic Waves120× since 2002

The equation of the electric field of an electromagnetic wave propagating through free space is given by :

E=\sqrt{377}\sin(6.27\times10^3t-2.09\times10^{-5}x)

N/C. The average power of the electromagnetic wave is

\left(\frac{1}{\alpha}\right)

W/m

^2

. The value of

\alpha

is ______ (Take

\sqrt{\frac{\mu_0}{\epsilon_0}}=377

in SI units)

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2026 Electromagnetic Waves Question with Solution (23 Jan Morning shift, Q48) | JEE Arc