PhysicsMedium120×since 2002Q6817The energy density associated with electric field E⃗\vec{E}E and magnetic field B⃗\vec{B}B of an electromagnetic wave in free space is given by (ϵ0−\left(\epsilon_{0}-\right.(ϵ0− permittivity of free space, μ0−\mu_{0}-μ0− permeability of free space)AUE=ϵ0E22,UB=B22μ0U_{E}=\frac{\epsilon_{0} E^{2}}{2}, U_{B}=\frac{B^{2}}{2 \mu_{0}}UE=2ϵ0E2,UB=2μ0B2BUE=E22ϵ0,UB=μ0B22U_{E}=\frac{E^{2}}{2 \epsilon_{0}}, U_{B}=\frac{\mu_{0} B^{2}}{2}UE=2ϵ0E2,UB=2μ0B2CUE=ϵ0E22,UB=μ0B22U_{E}=\frac{\epsilon_{0} E^{2}}{2}, U_{B}=\frac{\mu_{0} B^{2}}{2}UE=2ϵ0E2,UB=2μ0B2DUE=E22ϵ0,UB=B22μ0U_{E}=\frac{E^{2}}{2 \epsilon_{0}}, U_{B}=\frac{B^{2}}{2 \mu_{0}}UE=2ϵ0E2,UB=2μ0B2Check answerSkip