PhysicsEasy120×since 2002Q6824The electric field of an electromagnetic wave in free space is represented as E→=E0cos(ωt−kz)i^\overrightarrow{\mathrm{E}}=\mathrm{E}_0 \cos (\omega \mathrm{t}-\mathrm{kz}) \hat{i}E=E0cos(ωt−kz)i^. The corresponding magnetic induction vector will be :AB→=E0Ccos(ωt+kz)j^\overrightarrow{\mathrm{B}}=\mathrm{E}_0 \mathrm{C} \cos (\omega \mathrm{t}+\mathrm{k} z) \hat{j}B=E0Ccos(ωt+kz)j^BB→=E0Ccos(ωt−kz)j^\overrightarrow{\mathrm{B}}=\frac{\mathrm{E}_0}{\mathrm{C}} \cos (\omega \mathrm{t}-\mathrm{kz}) \hat{j}B=CE0cos(ωt−kz)j^CB→=E0Ccos(ωt−kz)j^\overrightarrow{\mathrm{B}}=\mathrm{E}_0 \mathrm{C} \cos (\omega \mathrm{t}-\mathrm{k} z) \hat{j}B=E0Ccos(ωt−kz)j^DB→=E0Ccos(ωt+kz)j^\overrightarrow{\mathrm{B}}=\frac{\mathrm{E}_0}{\mathrm{C}} \cos (\omega \mathrm{t}+\mathrm{kz}) \hat{j}B=CE0cos(ωt+kz)j^Check answerSkip