PhysicsHard120×since 2002Q6755The electric field of a plane polarized electromagnetic wave in free space at time t = 0 is given by an expression E→(x,y)=10j^cos[(6x+8z)].\overrightarrow E \left( {x,y} \right) = 10\widehat j\cos \left[ {\left( {6x + 8z} \right)} \right].E(x,y)=10jcos[(6x+8z)]. The magnetic field B→\overrightarrow BB(x,z, t) is given by −-− (c is the velocity of light)A1c(6k^+8i^)cos[(6x+8z−10ct)]{1 \over c}\left( {6\hat k + 8\widehat i} \right)\cos \left[ {\left( {6x + 8z - 10ct} \right)} \right]c1(6k^+8i)cos[(6x+8z−10ct)]B1c(6k^−8i^)cos[(6x+8z−10ct)]{1 \over c}\left( {6\widehat k - 8\widehat i} \right)\cos \left[ {\left( {6x + 8z - 10ct} \right)} \right]c1(6k−8i)cos[(6x+8z−10ct)]C1c(6k^+8i^)cos[(6x−8z+10ct)]{1 \over c}\left( {6\hat k + 8\widehat i} \right)\cos \left[ {\left( {6x - 8z + 10ct} \right)} \right]c1(6k^+8i)cos[(6x−8z+10ct)]D1c(6k^−8i^)cos[(6x−8z+10ct)]{1 \over c}\left( {6\hat k - 8\widehat i} \right)\cos \left[ {\left( {6x - 8z + 10ct} \right)} \right]c1(6k^−8i)cos[(6x−8z+10ct)]Check answerSkip