PhysicsHard120×since 2002Q6813The electric field in an electromagnetic wave is given as E→=20sinω(t−xc)j→NC−1\overrightarrow{\mathrm{E}}=20 \sin \omega\left(\mathrm{t}-\frac{x}{\mathrm{c}}\right) \overrightarrow{\mathrm{j}} \mathrm{NC}^{-1}E=20sinω(t−cx)jNC−1 where ω\omegaω and ccc are angular frequency and velocity of electromagnetic wave respectively. The energy contained in a volume of 5×10−4 m35 \times 10^{-4} \mathrm{~m}^{3}5×10−4 m3 will be (Given ε0=8.85×10−12C2/Nm2\varepsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} / \mathrm{Nm}^{2}ε0=8.85×10−12C2/Nm2 )A17⋅7×10−13 J17 \cdot 7 \times 10^{-13} \mathrm{~J}17⋅7×10−13 JB28⋅5×10−13 J28 \cdot 5 \times 10^{-13} \mathrm{~J}28⋅5×10−13 JC8⋅85×10−13 J8 \cdot 85 \times 10^{-13} \mathrm{~J}8⋅85×10−13 JD88⋅5×10−13 J88 \cdot 5 \times 10^{-13} \mathrm{~J}88⋅5×10−13 JCheck answerSkip